Electromagnetic induction — cutting field lines
An e.m.f. is induced whenever a conductor cuts magnetic field lines, or the field linking a coil changes; in a complete circuit it drives an induced current. It grows with faster motion, a stronger field and more turns, and reverses if the motion or the poles reverse. The a.c. generator applies this: a coil rotating in a field is joined by slip rings and brushes, so its output reverses every half-turn — a sine curve of e.m.f. against time.
Motor effect — force on a current in a field
A current-carrying wire across a magnetic field feels a force — the motor effect. Direction: Fleming's left-hand rule (First finger Field, seCond finger Current, thuMb Motion). In a d.c. motor the two coil sides feel opposite forces, giving a turning couple; a split-ring commutator reverses the coil current each half-turn so it turns one way. More turns, more current and a stronger field raise the turning effect — but a smaller magnet is not always weaker.
Transformer — changing field, a.c. only
A transformer has primary and secondary coils on a soft-iron core. Alternating current in the primary makes a changing magnetic field in the core, inducing an alternating e.m.f. in the secondary — so it works on a.c. only, never on steady d.c. Turns and p.d. follow , so steps the p.d. up and steps it down. An ideal transformer wastes no power, , so raising the voltage lowers the current in proportion.
Drawn from real examiner reports.
Slip rings ≠ split-ring commutator
An a.c. generator uses slip rings — two continuous rings that keep the coil on the same brushes throughout, so the naturally alternating e.m.f. reaches the circuit unchanged. A d.c. motor uses a split-ring commutator, whose gap swaps the connections every half-turn to keep the coil turning one way. Pairing to learn: generator → slip rings, motor → commutator.
Flagged Jun 2022 P41 Q6bii; Nov 2023 P43 Q6c
Induced e.m.f. ignores resistance
The size of an induced e.m.f. depends on the speed of the movement, the strength of the field and the number of turns — never on the conductor's resistance. Resistance would change the induced current in a complete circuit, but the e.m.f. itself is set only by how fast field lines are cut.
Flagged Jun 2023 P22 Q38
A current's field: circles, not lines
Around a straight wire the field is concentric circles, in planes at right angles to the wire — not straight lines. Their direction comes from the right-hand grip rule and reverses when the current reverses, so arrow them. A solenoid instead gives a bar-magnet field, uniform inside with N and S ends; more current, or a soft-iron core, strengthens it.
Flagged Jun 2023 P11 Q38, P12 Q36; Nov 2023 P11 Q38
The core is soft iron, not copper
An electromagnet or transformer core is soft iron, because it magnetises and demagnetises easily. Copper is the wrong answer — copper is the coil winding, not the core. Steel is wrong too: steel keeps its magnetism, so it makes a permanent magnet rather than a core that must follow a changing current.
Flagged Jun 2023 P11 Q38, P12 Q36; Nov 2023 P11 Q38
No force when current is parallel
The motor-effect force is greatest when the current is perpendicular to the field and zero when the current runs parallel to it — a wire lying along the field lines cuts none and feels nothing. Reversing the current reverses the force; reversing the field reverses it as well; reversing both leaves the force unchanged.
Flagged Jun 2022 P43 Q12cii; Jun 2023 P11 Q40
High voltage ≠ carrying more power
Transmitting at high voltage does not send more power, and it does not lower the cable resistance — that is fixed by the cable. The real chain: for a fixed power, , so a high voltage means a small current; the cable loss is , which depends on the square of the current, so a small current wastes far less.
Flagged Jun 2022 P21 Q38; Nov 2022 P42 Q9cii
e.m.f. (source) ≠ p.d. (component)
e.m.f. is the work done per unit charge by the source — the energy a generator or cell supplies to each coulomb. p.d. is the energy transferred from each coulomb by a component. Both are measured in volts, but they describe opposite directions of energy transfer, and questions ask you to distinguish them.
Flagged Jun 2023 P41 Q9c
A routine for transformer numbers
Choose the equation first — for turns and p.d., for currents. Substitute the three known values, rearrange for the unknown, then write the unit (V, A, or a plain number of turns). A numerical answer with no unit is routinely penalised.
Never flip the turns ratio
Solving for the secondary p.d., keep the primary quantities together: . Multiplying by instead turns a step-up answer into a step-down one. Sanity-check every result: more turns on the secondary must give a larger secondary p.d.
Describe vs explain the e.m.f. graph
Describe the generator output: a sine curve of e.m.f. (V) against time (s), constant amplitude/period. Explain: the e.m.f. peaks when the coil sides cut field lines fastest and is zero when they move parallel to it. State = one line; never describe when asked to explain.
Cambridge 0654 spec reference: Section P4 "Electricity and magnetism", sub-topic P4.5. In the 0654 syllabus this whole topic is Supplement / Extended content -- there is no Core electromagnetic-induction material. It covers electromagnetic induction and the factors affecting the induced e.m.f.; the a.c. generator; magnetic field patterns from currents in wires and solenoids; the force on a current-carrying conductor (motor effect) and the d.c. motor; and the transformer, including , , and high-voltage transmission with cable losses.
Symbol note: e.m.f. = electromotive force; p.d. = potential difference; a.c. = alternating current; d.c. = direct current.
Transformer turns-ratio: where = primary p.d. (V), = secondary p.d. (V), = number of primary turns, = number of secondary turns.
Ideal transformer power (100% efficient): where = primary current (A) and = secondary current (A).
Power loss in a transmission cable: where = power dissipated as heat (W), = current in the cable (A), = cable resistance ().
(Extended) Define electromagnetic induction.
(Extended) A transformer has a primary coil of 1000 turns and a secondary coil of 50 turns. The primary coil is connected to a 230 V a.c. supply.
Calculate the potential difference across the secondary coil. State whether this is a step-up or step-down transformer. (3 marks)