Build the vector by following a route
Any required vector is a sum of journeys: , where . Express everything in the given base vectors and , then collect terms.
Use the section/midpoint formula
If divides with then . The midpoint is the special case .
Parallel ⇔ scalar multiple
means is parallel to and times its length; if they also share a point, the points are collinear. This is how vector "proofs" are argued.
Drawn from real examiner reports.
Sloppy notation — equating vectors to scalars
Writing a vector equal to a number, or dividing one vector by another, loses the communication marks on a top-grade question.
Sign errors and missing brackets
Dropping a bracket when expanding something like flips a sign and ruins the simplification.
Assuming a false relationship between vectors
Guessing e.g. instead of finding two genuinely independent expressions for the same vector and equating them.
Find the same vector two ways, then equate
For "find the ratio / value" parts, write the target vector along two different routes (using a parameter where needed) and equate the coefficients of and .
Every vector between labelled points is a chain of journeys you already know: Write each piece in the base vectors and , keep brackets, then collect like terms.
Why must (not ) when , ?
In triangle , and . The point lies on such that .
Find in terms of and , giving your answer in its simplest form.
(Diagram NOT accurately drawn.)