Linear nth term: dn + (first term − d)
For a sequence going up by a fixed amount , the th term is plus a correction, e.g. 5, 8, 11, … has and nth term .
Quadratic nth term: half the second difference is the n² coefficient
If the second differences are constant and equal , the th term starts with ; subtract from each term and find the linear part of what is left.
Arithmetic series sum
, where is the first term and the common difference.
Drawn from real examiner reports.
Giving only the dn part of a linear nth term
Writing 3n (the common-difference part) without the constant, or writing the rule as an equation like n = 3n − 2.
Weak algebra when forming/solving the series equations
Setting up the sum formula but mishandling the term, or factorising the resulting quadratic in incorrectly.
Not halving the second difference
Using the whole second difference as the coefficient instead of half of it.
Test your rule on a couple of terms
Substitute into your nth-term rule and confirm it reproduces the sequence.
Find the common difference ; the nth term is . Give the full rule (not just ), and check it on .
How do you check an nth-term rule?
Find the th term of the sequence