Parallel: same m; perpendicular: −1/m
Parallel lines have equal m. For perpendicular lines the gradients multiply to −1, so the perpendicular gradient is −1/m (flip and change sign).
Gradient from two points
Gradient = (change in y) ÷ (change in x) = (y₂−y₁)/(x₂−x₁). Keep the points in the same order top and bottom.
y = mx + c reads straight off
m is the gradient (steepness) and c is the y-intercept (where the line crosses the y-axis). Rearrange any line into this form before reading either off.
Drawn from real examiner reports.
Inaccurate plotting / x = k vs y = k
Lines such as x + y = 7 were started correctly at 7 on one axis but joined to 8 on the other; x = 2 was drawn instead of y = 2.
Seen on recent higher-tier exams.
Using the wrong perpendicular gradient
Students gave m = 2 or m = −2 instead of the negative reciprocal, and forgot to rearrange the given equation into y = mx + c before reading the gradient.
Seen on a recent higher-tier exam.
Gradient is a number, not "2.5x"
Examiners were "surprised that many do not actually know what the gradient is" — values like 2.5x or 5/2x were commonly given. The gradient is a single numerical value.
Strongly highlighted on a recent higher-tier exam.
Reading gradient as run over rise
Gradient is , the change in over the change in . Turning it upside-down (run over rise) gives the reciprocal — e.g. reading where the true gradient is .
Only the x-term divided when rearranging
Rearranging to , divide EVERY term by 3: . Dividing only the -term and leaving as is a frequent slip.
Use a small table of values or the intercepts
Examiners noted very few students used a table of values or substituted x = 0 and y = 0 to plot a line. For x + y = 7, plot (7, 0) and (0, 7) and join with a ruler.
Rearrange before reading the gradient
Always rearrange a line into before you read off or take a negative reciprocal. Reading the gradient from directly is where most perpendicular-line marks are lost.
Find c by substituting a point
Once you know the gradient , put the given point's coordinates into and solve for — do not stop at the gradient. Then state the full equation .
Gradient of a line parallel to y = 4x + 1?
A line is parallel to and passes through . Find its equation.