Reversible reactions and dynamic equilibrium
Some reactions are reversible — the products can react to re-form the reactants, shown by the equilibrium symbol . In a sealed (closed) container a reversible reaction reaches dynamic equilibrium, defined by two things: the forward and reverse reactions occur at the same rate, and the concentrations stay constant (constant, not equal). "Dynamic" means both reactions still happen — the opposing rates cancel out.
What shifts equilibrium — and what does not
Changing conditions shift the position of equilibrium (4CH1 does not credit Le Chatelier — explain via energy or moles of gas). Temperature: increase → endothermic direction, decrease → exothermic. Pressure (gases): increase → fewer moles of gas, decrease → more moles. Catalyst: speeds forward and reverse rates equally, so no change to position or yield — equilibrium is just reached faster.
Drawn from real examiner reports.
Giving a yield change without the shift
When asked about a pressure or temperature change, writing only "the yield decreases" scores half marks at best. The mark scheme needs a clear statement of which way the equilibrium shifts (left/right) and the reason (fewer moles of gas, or the endothermic/exothermic direction). A bare yield statement reads like a 50:50 guess and is not credited alone.
June 2024 Paper 2CR Q7(a)(i) — candidates who said the yield of ethanol decreases but did not state the equilibrium "shifts to the left-hand side" lost the first marking point.
A catalyst is not forward-only
On a reversible reaction a catalyst increases the rate of both the forward and the backward reaction by the same amount, so the yield is unchanged — only the time to reach equilibrium falls. Many write at length on activation energy (not asked) but never state that both rates rise equally. Never write that a catalyst raises the yield.
June 2024 Paper 2CR Q7(a)(ii) — candidates focused on the forward reaction only; many gave unnecessary detail on how a catalyst works but failed to state that forward and backward rates increase equally.
Constant concentrations are not equal ones
At dynamic equilibrium the concentrations of reactants and products stay constant — this does not mean they are equal to each other. There may be far more product than reactant (or vice versa); what matters is that the amounts stop changing. "Equal concentrations" is a classic wrong answer.
June 2023 Paper 2CR Q7(a)(i) — a common incorrect answer implied the product and reactant concentrations are equal rather than constant.
It is the rates that are equal, not amounts
It is the forward and reverse rates that are equal at equilibrium — not the amounts of reactants and products. Dropping the word "rate" (writing "the reactions are equal" or "the amounts are equal") loses the mark. The concentrations are merely constant; the two opposing rates are what balance so that nothing appears to change.
June 2023 Paper 2CR Q7(a)(i) — some candidates omitted the key word "rate", implying the amounts rather than the rates are equal.
Naming Le Chatelier earns nothing in 4CH1
In 4CH1, naming "Le Chatelier's principle" earns nothing — the specification does not require it. You must explain a shift in spec terms: the endothermic/exothermic direction for a temperature change, or fewer/more moles of gas for a pressure change. A bare "by Le Chatelier's principle" with no mechanism scores zero.
June 2023 Paper 2CR Q7(a)(iii) — answers had to state the exothermic/endothermic direction; bare references to Le Chatelier's principle scored nothing.
Equilibrium needs a sealed container
Dynamic equilibrium is only reached in a sealed (closed) container. If the system is open so a gas can escape, the reaction goes to completion instead of reaching equilibrium — the escaping product cannot react back. Always check the container is closed before describing an equilibrium.
(common Edexcel chemistry error)
Answer in two parts: shift + reason
Answer any conditions-change question in two parts: (1) state the shift — equilibrium moves left/right (yield up or down); (2) give the reason — temperature → endothermic/exothermic direction; pressure → fewer/more moles of gas. Never name Le Chatelier.
Pressure questions: count moles of gas first
For a pressure question, first count the moles of gas on each side. An increase in pressure shifts the equilibrium to the side with fewer moles of gas (a decrease shifts it to the side with more). State the shift direction, then the effect on the yield.
Catalyst answer: yield unchanged, just faster
For a catalyst on a reversible reaction the answer is always the same: the yield is unchanged, because the forward and reverse rates rise equally — equilibrium is reached faster. Do not dwell on activation energy; the equal-rates point carries the mark.
Effect of changing conditions on the position of equilibrium (no Le Chatelier required):
| Change | Equilibrium shifts towards… | Reason to quote |
|---|---|---|
| Increase temperature | the endothermic direction | the endothermic reaction is favoured |
| Decrease temperature | the exothermic direction | the exothermic reaction is favoured |
| Increase pressure (gases) | the side with fewer moles of gas | fewer gas molecules lowers the pressure |
| Decrease pressure (gases) | the side with more moles of gas | more gas molecules raises the pressure |
| Add a catalyst | no shift | forward and reverse rates rise equally |
What does the symbol in an equation tell you?
Anhydrous copper(II) sulfate is used to test for water. Construct its formula from the ions and .